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Mass from Density and Volume: Definition, Method and Examples

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Mass from Density and Volume: Definition, Method and Examples

To find mass from density and volume, multiply the density by the volume using the formula M=D×VM = D \times V. Because density represents the amount of mass per unit volume, multiplying it by the total volume gives the total mass.

What does mass from density and volume mean?

Mass is the amount of matter in an object, typically measured in grams (g\text{g}) or kilograms
(kg\text{kg}). Volume is the amount of space the object occupies, commonly measured in cubic centimeters (cm3\text{cm}^3) or cubic meters (m3\text{m}^3).


Density is a compound measure that acts as a unit rate, describing the mass per single unit of volume. When you know both the density of a material and its total volume, you can determine its total mass by scaling up that unit rate.

A small block representing a volume of 1 cubic centimeter and a mass of 5 grams is scaled up by a factor of 4 to form a larger block with a mass of 20 grams.

Rearrange the density relationship

The basic density formula is written as D=MVD = \dfrac{M}{V}. To find the mass when you know the density and the volume, you rearrange this equation by multiplying both sides by volume (VV).

This gives the direct relationship M=D×VM = D \times V.

A triangular relationship diagram showing mass at the top and density and volume at the bottom, indicating that mass equals density multiplied by volume.


The triangle provides a helpful visual shortcut: cover the MM at the top to see that you must multiply DD by VV at the bottom.

Multiply density by volume

To calculate the mass, substitute the known density and volume into the rearranged formula.

Method:

  1. Identify the given density and volume.
  2. Ensure their units are compatible.
  3. Multiply the density by the volume.
  4. State the mass with its correct unit.

Mass equals density times volume.

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Check units

Always verify that the units of volume match the volume component of the density unit before calculating.

If density is given in kilograms per cubic meter (kg/m3\text{kg/m}^3) and volume is given in cubic meters
(m3\text{m}^3), multiplying them cancels the m3\text{m}^3, leaving the mass correctly in kilograms (kg\text{kg}).

An equation showing the units for density and volume being multiplied. The cubic meters cancel out, leaving kilograms as the resulting unit of mass.

If the units do not match—for instance, if volume is in cm3\text{cm}^3 but density is in kg/m3\text{kg/m}^3—you must convert one of the measurements so they align perfectly before multiplying.

Solve contextual problems

When applying this formula to real-world objects, you may need to calculate the volume of a three-dimensional shape before finding its mass. Real-world engineering often uses compound measures like the pressure formula or flow rate, which require accurate mass and volume calculations.


Once the volume is determined from the object's dimensions, multiply that volume by the material's density to find the total mass.

A 3D steel block with dimensions of 10, 5, and 4 centimeters. A calculation shows its volume is 200 cubic centimeters and its mass is 1,560 grams.

Worked examples

Review these examples to see how to calculate mass with matching units, apply unit conversions, and verify your answers using the formula relationships.

Example 1: Finding mass with matching units


Question: An aluminum block has a volume of 150 cm3150\text{ cm}^3 and a density of 2.7 g/cm32.7\text{ g/cm}^3. What is its mass?


Method:

  1. Identify the given values: V=150 cm3V = 150\text{ cm}^3 and D=2.7 g/cm3D = 2.7\text{ g/cm}^3.
  2. Check units: Both values use cm3\text{cm}^3, so no conversion is needed.
  3. Multiply density by volume: M=2.7×150M = 2.7 \times 150.
  4. Calculate the result: M=405M = 405.

Answer: The mass is 405 g405\text{ g}.


Check: Since D=MVD = \dfrac{M}{V}, check that 405150=2.7 g/cm3\dfrac{405}{150} = 2.7\text{ g/cm}^3.


Example 2: Finding mass with unit conversion


Question: A gold bar has a volume of 500 cm3500\text{ cm}^3. The density of gold is 19,300 kg/m319{,}300\text{ kg/m}^3. What is the mass of the gold bar in kilograms?


Method:

  1. Identify the given values: V=500 cm3V = 500\text{ cm}^3 and D=19,300 kg/m3D = 19{,}300\text{ kg/m}^3.
  2. Convert the volume to match the density unit: Since 1 m3=1,000,000 cm31\text{ m}^3 = 1{,}000{,}000\text{ cm}^3, divide 500500 by 1,000,0001{,}000{,}000 to get V=0.0005 m3V = 0.0005\text{ m}^3.
  3. Multiply density by volume: M=19,300×0.0005M = 19{,}300 \times 0.0005.
  4. Calculate the result: M=9.65M = 9.65.

Answer: The mass is 9.65 kg9.65\text{ kg}.


Check: Convert the mass to grams to verify: 9.65 kg=9,650 g9.65\text{ kg} = 9{,}650\text{ g}. Using the density of gold in g/cm3\text{g/cm}^3 (19.3 g/cm319.3\text{ g/cm}^3) multiplied by 500 cm3500\text{ cm}^3 also gives 9,650 g9{,}650\text{ g}.


Example 3: Verifying the mass calculation


Question: A block of ice has a volume of 2,000 cm32{,}000\text{ cm}^3. The density of ice is 0.92 g/cm30.92\text{ g/cm}^3. Calculate the mass and use the density formula to check your answer.


Method:

  1. Identify the given values: V=2,000 cm3V = 2{,}000\text{ cm}^3 and D=0.92 g/cm3D = 0.92\text{ g/cm}^3.
  2. Check units: Both values use cm3\text{cm}^3, so no conversion is needed.
  3. Multiply density by volume: M=0.92×2,000M = 0.92 \times 2{,}000.
  4. Calculate the result: M=1,840M = 1{,}840.

Answer: The mass is 1,840 g1{,}840\text{ g}.


Check: Rearrange the density formula to D=MVD = \dfrac{M}{V}. Divide 1,8401{,}840 by 2,0002{,}000. The result is 0.92 g/cm30.92\text{ g/cm}^3, verifying the calculation is correct.

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Common mistakes

A frequent error is dividing the values instead of multiplying them. Always remember the correct rearrangement M=D×VM = D \times V. Dividing density by volume will not give you the mass.


Another common mistake is ignoring unit mismatches. Multiplying a density measured in kg/m3\text{kg/m}^3 by a volume in cm3\text{cm}^3 results in an incorrect answer. You must convert one of the units so they match. When converting volume, remember that cubic units scale by the cube of the length conversion factor. For example, 1 m31\text{ m}^3 is equal to 1,000,000 cm31{,}000{,}000\text{ cm}^3, not 100 cm3100\text{ cm}^3.

Frequently asked questions

Here are answers to common questions about calculating mass, density, and volume.


What is the formula to find mass from density and volume?

The correct formula is M=D×VM = D \times V, where MM stands for mass, DD for density, and VV for volume.


How do you find volume if you know mass and density?

You can rearrange the original density formula to isolate volume. This gives the relationship V=MDV = \dfrac{M}{D}.


What units are used for mass?

Common metric units for mass include grams (g\text{g}) and kilograms (kg\text{kg}). The appropriate unit often depends on the density measurement provided in the problem.

Practice questions

Question

A visual equation showing density in grams per cubic centimeter being multiplied by a volume in cubic centimeters to find the unknown mass.

Which equation correctly shows how the units cancel out when finding mass from density (g/cm3\text{g/cm}^3) and volume (cm3\text{cm}^3)?

  • gcm3×cm3=g\dfrac{\text{g}}{\text{cm}^3} \times \text{cm}^3 = \text{g}

  • cm3g×cm3=g\dfrac{\text{cm}^3}{\text{g}} \times \text{cm}^3 = \text{g}

  • gcm3÷cm3=g\dfrac{\text{g}}{\text{cm}^3} \div \text{cm}^3 = \text{g}

  • g×cm3=g/cm3\text{g} \times \text{cm}^3 = \text{g/cm}^3

Answer:

gcm3×cm3=g\dfrac{\text{g}}{\text{cm}^3} \times \text{cm}^3 = \text{g}

Question

A piece of metal has a volume of 250 cm3250\text{ cm}^3 and a density of 8 g/cm38\text{ g/cm}^3. What is its mass?

  • 200 g200\text{ g}

  • 2,000 g2{,}000\text{ g}

  • 31.25 g31.25\text{ g}

  • 20,000 g20{,}000\text{ g}

Answer:

2,000 g2{,}000\text{ g}

Question

A 3D rectangular room filled with air. The room has dimensions of 4 meters, 3 meters, and 2 meters, and the air density is 1.2 kilograms per cubic meter.

The rectangular room shown in the diagram is filled with air. What is the total mass of the air inside the room?

  • 28.8 kg28.8\text{ kg}

  • 24 kg24\text{ kg}

  • 20 kg20\text{ kg}

  • 10.8 kg10.8\text{ kg}

Answer:

28.8 kg28.8\text{ kg}

Question

A piece of metal has a volume of 0.5 m30.5\text{ m}^3 and a density of 4,000 kg/m34{,}000\text{ kg/m}^3. A student calculates the mass by evaluating 4,000÷0.54{,}000 \div 0.5 to get 8,000 kg8{,}000\text{ kg}. What mistake did the student make?

  • They divided density by volume instead of multiplying them.

  • They forgot to convert cubic meters to cubic centimeters.

  • They multiplied volume by density instead of dividing them.

  • They used the wrong units for the final mass result.

Answer:

They divided density by volume instead of multiplying them.

Question

A wooden block has a volume of 500 cm3500\text{ cm}^3 and a density of 600 kg/m3600\text{ kg/m}^3. What is its mass in grams?

  • 300 g300\text{ g}

  • 300,000 g300{,}000\text{ g}

  • 1.2 g1.2\text{ g}

  • 3,000 g3{,}000\text{ g}

Answer:

300 g300\text{ g}

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