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Divisibility Rules: Guide and Examples

MathPublished

Divisibility Rules: Guide and Examples

Divisibility rules are quick tests that determine whether one whole number divides another exactly without performing full division. A number is divisible by a second number if dividing them leaves a remainder of zero. These rules save time by using digit patterns, sums, and place-value properties instead of calculating long division.


Divisibility means a number can be split into equal groups with no remainder.

Divisibility Rules: Definition and Notation

A divisibility rule is a shortcut to discover whether a number is a factor of a larger number. When checking if a number divides perfectly without performing the division mathematically, we use these rules to inspect the number's individual digits.


In mathematics, a vertical bar symbol is used to denote divisibility. The notation 3∣123 \mid 12 is read as "33 divides 1212." This means that 1212 is divisible by 33, leaving a remainder of zero. If a number does not divide perfectly, we write a slashed bar, such as 5∤125 \nmid 12, which means "55 does not divide 1212."

Understanding these tests helps to quickly identify factors, simplify fractions, and determine whether a number is prime.

Rules or Reference Table

Different numbers have different tests based on their patterns. Some rules examine only the final digit, some check the sum of all digits, and others combine multiple rules.

Here is the reference table for the most common divisibility rules from 22 to 1212:

Divisor

Divisibility Rule

Example

22

The last digit is even (0,2,4,6,80, 2, 4, 6, 8).

3,1563,15\mathbf{6} is divisible by 22.

33

The sum of all digits is divisible by 33.

414→4+1+4=9414 \rightarrow 4+1+4=9 (divisible by 33).

44

The last two digits form a number divisible by 44.

2, ⁣712→122,\!7\mathbf{12} \rightarrow 12 is divisible by 44.

55

The last digit is 00 or 55.

89589\mathbf{5} is divisible by 55.

66

The number is divisible by both 22 and 33.

132132 is even and 1+3+2=61+3+2=6.

88

The last three digits form a number divisible by 88.

5, ⁣016→165,\!\mathbf{016} \rightarrow 16 is divisible by 88.

99

The sum of all digits is divisible by 99.

288→2+8+8=18288 \rightarrow 2+8+8=18 (divisible by 99).

1010

The last digit is 00.

5, ⁣4305,\!43\mathbf{0} is divisible by 1010.

1111

The alternating sum and difference of the digits is 00 or a multiple of 1111.

3,619→3−6+1−9=−113,619 \rightarrow 3-6+1-9=-11.

1212

The number is divisible by both 33 and 44.

324→324 \rightarrow sum is 99 (yes for 33), ends in 2424 (yes for 44).

When a rule asks to check two other numbers (like the rule for 66 checking 22 and 33), those two numbers must be coprime, meaning they share no common factors other than 11.

A flowchart showing that testing a number for divisibility by 12 involves checking if it is divisible by both 3 and 4.

Why It Works

Divisibility rules work reliably because of the properties of the base-ten number system and place value.


For example, when checking divisibility by 44, we only look at the last two digits. Why? Because every hundred is a multiple of 100100, and 100100 is perfectly divisible by 44 (100÷4=25100 \div 4 = 25).


Any number of hundreds, thousands, or millions will also be perfectly divisible by 44. The only part of the number that might not divide perfectly is the remainder formed by the tens and ones digits.


The structure of place value means large portions of a number are guaranteed to be divisible by certain factors.


A place-value breakdown of 736 showing that 700 is guaranteed to be divisible by 4, leaving only 36 to be checked.

Similarly, the rule for 33 and 99 works because every power of 1010 is exactly one more than a multiple of 99 (10=9+110 = 9 + 1, 100=99+1100 = 99 + 1). The multiples of 99 are discarded, and only the sum of the remaining single digits needs to be tested to determine divisibility.

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Visual Worked Examples

Using these tests prevents unnecessary long division and ensures accuracy.


Example 1: Divisibility by 9

Question: Is 4,8514,851 divisible by 99?

Method:

  1. Find the sum of all digits in the number.
  2. The sum is 4+8+5+14 + 8 + 5 + 1.
  3. Calculate the total: 1818.
  4. Check if 1818 is divisible by 99. Since 18÷9=218 \div 9 = 2, the rule passes.

Answer: Yes, 4,8514,851 is divisible by 99.

Check: 4,851÷9=5394,851 \div 9 = 539, leaving no remainder.


Example 2: Composite rule

Question: Is 2,5082,508 divisible by 66?

Method:

  1. A number is divisible by 66 if it is divisible by both 22 and 33.
  2. Check the rule for 22: The last digit is 88, which is even. The rule for 22 passes.
  3. Check the rule for 33: Sum the digits 2+5+0+8=152 + 5 + 0 + 8 = 15.
  4. Since 15÷3=515 \div 3 = 5, the rule for 33 passes.
  5. Because both rules pass independently, the entire number is divisible by 66.

Answer: Yes, 2,5082,508 is divisible by 66.

Check: 2,508÷6=4182,508 \div 6 = 418.


Example 3: Alternating sum for 11

Question: Is 8,2948,294 divisible by 1111?

Method:

  1. The rule for 1111 requires an alternating sum. Add and subtract the digits in order from left to right.
  2. The sequence is: +8−2+9−4+8 - 2 + 9 - 4.
  3. Calculate the result step by step: 8−2=68 - 2 = 6, 6+9=156 + 9 = 15, 15−4=1115 - 4 = 11.
  4. If the final answer is 00 or a multiple of 1111, the number is divisible by 1111. The result is 1111, which passes the test.

Answer: Yes, 8,2948,294 is divisible by 1111.

Check: 8,294÷11=7548,294 \div 11 = 754.


A diagram showing the alternating signs plus and minus applied to the digits of 8294 to yield a sum of 11.

Common Mistakes and Exceptions

A frequent mistake is applying the rule for 22 or 55 to other numbers. Because divisibility by 22 depends only on the last digit, some learners mistakenly assume that any number ending in 33 is divisible by 33, or any number ending in 44 is divisible by 44.

The rule for 44 strictly requires checking the last two digits combined as a single number, not just the final digit alone.


Another common error happens when testing for divisibility by composite numbers like 88 and 1212. The factors used in a composite rule must be coprime. For example, testing for 1212 works by checking 33 and 44 (since they share no factors other than 11).


You cannot test for 1212 by checking 22 and 66, because 22 and 66 share a common factor of 22. The number 1818 is divisible by both 22 and 66, but it is not divisible by 1212.

Applications

Understanding these tests is highly useful when simplifying mathematical fractions and finding common denominators.


When searching for the factors of a number, applying divisibility rules guarantees that no factor is missed. They are incredibly helpful for distinguishing prime vs composite numbers. If any divisibility test (other than 11 and the number itself) succeeds, you have successfully proven that the number is a composite number.


These rules also speed up finding the prime factorization of large values. Instead of guessing factors randomly when constructing a factor tree, you can immediately apply the tests for 22, 33, or 55 to confidently discover the prime branches of your tree.

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Practice questions

Question

An array of 17 circles arranged into 3 full rows of 5 circles, plus a final row with 2 circles.


Based on the array model of 1717 items, which statement is true regarding divisibility?

  • 1717 is divisible by 55 because it forms rows of 55.

  • 1717 is divisible by 33 because there are 33 full rows.

  • 1717 is not divisible by 55 because there is a remainder of 22.

  • 1717 is perfectly divisible by 22 because the remainder is 22.

Answer:

1717 is not divisible by 55 because there is a remainder of 22.

Question

Which of the following numbers is divisible by 44?

  • 3,1143,114

  • 8,0268,026

  • 5,4325,432

  • 7,9187,918

Answer:

5,4325,432

Question

A five-digit number is written as 42,61□42,61\square, where the last digit is missing. Which single digit can be placed in the box to make the number divisible by 99?

  • 22

  • 33

  • 55

  • 77

Answer:

55

Question

A flowchart testing if 18 is divisible by 12 by wrongly checking if it is divisible by 2 and 6.

A student uses the flowchart above to test if 1818 is divisible by 1212. They conclude that because 1818 is divisible by both 22 and 66, it must be divisible by 1212. Why is this reasoning mathematically incorrect?

  • The student calculated the division for 22 and 66 incorrectly.

  • A number can never be tested for divisibility using two smaller factors.

  • The factors 22 and 66 are not coprime, so they cannot be used to test for 1212.

  • 1818 is actually divisible by 1212, so the flowchart conclusion is true.

Answer:

The factors 22 and 66 are not coprime, so they cannot be used to test for 1212.

Question

Which of the following numbers is divisible by both 55 and 1111?

  • 3,1453,145

  • 6,1056,105

  • 8,2108,210

  • 4,9154,915

Answer:

6,1056,105

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